Physics, asked by avs56, 7 months ago

if 4000 joule of work is required transfer 40 coulomb of charge between two points of a resistor of 25 ohm what is the current passing​

Answers

Answered by piyush726
0

Answers

12.64 Amp

Explanation

W = v^2/r

4000 = v^2/25

v^2 = 4000 × 25

v = 316.22

v = Ir

316.22 = I (25)

I = 316.22/25

I = 12.64 Amp

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