if 4000 joule of work is required transfer 40 coulomb of charge between two points of a resistor of 25 ohm what is the current passing
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12.64 Amp
Explanation
W = v^2/r
4000 = v^2/25
v^2 = 4000 × 25
v = 316.22
v = Ir
316.22 = I (25)
I = 316.22/25
I = 12.64 Amp
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