Question

if 41 , 40 , m forms a pythogorean triplet where 41 is beggest number , Find the value of m

Answer 1

Answer:

9

Step-by-step explanation:

a²=b²+c² where a is the highest

41²=40²+c²

1681=1600+c²

1681-1600=c²

c²=81

c=√81

c=9

value of m=c=9