Question

if 41+41=17, 52+52=29, 63+63=45 then 98+98=?

Answer 1

Given :

41 + 41 = 17

52 + 52 = 29

63 + 63 = 45

To find :

The value of 98 + 98.

Solution :

Step 1 of 2 :

From the given numbers we can obtain that, the product of first digit in each number is added to the product of second digit.

Therefore,

41 + 41 = 17

4 × 4 = 16

1 × 1 = 1

16 + 1 = 17

52 + 52 = 29

5 × 5 = 25

2 × 2 = 4

25 + 4 = 29

63 + 63 = 45

6 × 6 = 36

3 × 3 = 9

36 + 9 = 45

Step 2 of 2 :

To find, 98 + 98

9 × 9 = 81

8 × 8 = 64

81 + 64 = 145

98 + 98 = 145

Final answer :

If, 41 + 41 = 17

52 + 52 = 29

63 + 63 = 45

Then, 98 + 98 = 145

Answer 2

Answer:

$98 +98=145$

Step-by-step explanation:

We have been given that,

$41+41= 17\\52+52 =29\\63+63= 45$

We have to find the value of  $98+98$

As for our first step, the product of the first digit of every number is added to the product of the second digit. From this information, we can infer that,

• $41+41=17$

⇒ $4 \times 4 = 16$

⇒ $1 \times 1 = 1$

⇒ $16 + 1 = 17$

• $52 +52=29$

⇒ $5 \times 5 = 25$

⇒ $2 \times 2 =4$

⇒ $25 + 4 =29$

• $63 +63 = 45$

⇒ $6 \times 6 = 36$

⇒ $3 \times 3 =9$

⇒ $36 + 9 =45$

Now, we can easily calculate the value of $98 +98$ by following similar steps again.

• $98+98= \ ?$

⇒ $9 \times 9 =81$

⇒ $8 \times 8 =64$

⇒ $81 + 64 = 145$

∴ $98 +98 = 145$

Hence, the value of $98 +98$ is $145$.

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