Question

if 41+41=17 , 52+52=29 , 63+63=45 , then 98+98=___​

Answer 1

Answer:

63

explanation

41+41=17

52+52=29

63+63=45

98+98=63.

because 17+(12)=29

29+(16)=45

45+(18)=63.

even numbers are add

Answer 2

Answer:

The sum of 98 + 98 = 145.

Step-by-step explanation:

Given the sum of two numbers as 41 + 41 = 17

• If we multiply the first two digits of both the numbers, $4\times 4=16$
• And multiply the second two digits of both the numbers, $1\times 1=1$
• Adding both the results, 16 + 1 = 17

Applying the same logic to the second sum: 52 + 52 = 29

• Product of $5\times 5=25$ and $2\times 2=4$
• Sum of the results is 25 + 4 = 29

Then for the third sum: 63 + 63 = 45

• Product of $6\times 6=36$ and $3\times 3=9$
• And the sum of the results is 36 + 9 = 45.

Applying the same logic to the sum, 98 + 98

• Multiply the first two digits of both the numbers, $9\times 9=81$
• And multiply the second two digits, $8\times 8=64$
• Adding both the results, 81 + 64 = 145

Therefore, the sum of 98 + 98 = 145.

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