Question

If 41sinA=40 show that tanA/tan^2A-1=360/1519

Answer 1

easyy !!!

See the step by step explanation:

41 sinA = 40

thus

sin A = 40/41 .............(1)

now ...

sin A= perpendicular/ hypotenuse

cos A= base / hypotenuse

tan A= perpendicular / base

thus by pythagoras theorem

(perpendicular)^2 + (base)^2 = (hypotenuse)^2

from (1)

(41)^2 = (40)^2 + (base)^2

on solving

base = 9

tanA / ( tan^2A -1 )

= ( 40/9 ) / ( (1600/81) - 1 ) = 360 / 1519

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