Question

If 41y5 is a multiple of 9 , where y is a dijit, what
is the value of y ?​

Answer 1

Answer:

Here is your answer for your question

Answer 2

Step-by-step explanation:

The divisibility test for 9 states that, “A number is divisible by 9 if and only if the sum of its digits is a multiple of 9 "

That is, if the sum of the digits of a number is 9,18,27 etc., then only the number is divisible by 9

The number given is 21y5

So, first we will check whether the sum can be 9

2+1+y+5=9

8+y=9

y=1

So we got a non-negative number in the range [0,9)

Thus y=1 will make the number divisible by 9

Infact,

21159=235

Hope that helps :)

I have one question in which std you are

please tell fast