if 41y688 is exactly divisible by 3, what is the least value of y
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Step-by-step explanation:
so dear...here divisibility of 3 is sum of all numbers should be divisible by 3 so
1st add all digits except y 4+1+6+8+8=27 which is exactly divisible by 3 so no need of adding anhthing therefore y will be 0
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