Math, asked by poonam5391, 1 year ago

If 41z5 is a multiple of 3, where z is a digit what is the value of z?

Answers

Answered by sanjay338
0

Answer:

2,5,8

Step-by-step explanation:

there r many possible answers

divisibility rule for 3 is sum of digits should be divisible by 3

Answered by dhayahardhaya
0

Answer:

the possible values of z are 2,5,8

Step-by-step explanation:

for multiple of 3 ,the sum of all digits must be divisible by 3

so we have 4+1+z+5 = 3k where k is a integer

and 0 < z < 9

by this we have

3k = 10 + z

by putting k = 4 we have z = 2

by putting k = 5 we have z = 5

by putting k = 6 we have z = 8

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