Question

If 42# 32=14,32 #12=8,
91# 10=9 then 67#12=?​

Answer 1

Given :  42# 32=14,32 #12=8,   91# 10=9

To find : 67#12=

Solution:

42 # 3 2= 14

(4 * 2)  + ( 3 * 2)

= 8 + 6

= 14

32 #12=8

(3 * 2)  + ( 1 * 2)

= 6 + 2

= 8

91# 10=9

= ( 9 * 1) + ( 1 * 0)

= 9 + 0

= 9

67#12=

= ( 6 * 7)  + (1 * 2)

= 42 + 2

= 44

Hence  67#12= 44

Logic is   ab #cd= x

=> (a * b)  + (c * d)  = x

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