Question

If 4200J of heat energy are required to vaporise 5g of ethanol at its boiling point, what is the specific latent heat of vaporation of ethanol?

Answer 1

Solution

Q=quantity of heat energy=4200J

M=mass=5g

Lv=specific latent heat of vaporization= ?

Convert 5g to kg:

5g= 0.005kg

Lv=Q/m

Lv= 4200J/0.005kg

Lv=840000J/kg

I hope this is helpful to you.