Question

if 43 times of two digit numbers is 34 times of two digit no .and sum of ( rnumber and reverse of the number) is 14 then what is the number?; if 43 times of two digit numbers is 34 times of two digit no .and sum of ( rnumber and reverse of the number) is 14 then what is the number?

Answer 1

43 time the no. = 34 time the reverse no.

43(10x+ y)=34(10y+ x)

430x+ 43y= 340y+34x

430x+43y-340y-34x=0

To solve this equation become

4x-3y=0 equation=2

Sum of no. And reverse no. Is 14

X+ Y= 14 equation=1

To solve both equation value of x and y

X= 6 and y= 8

number will be 68