Question

if 43p is divisible by 3, then what is the largest value P can take?

Answer 1

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Answer 2

All multiple of three that is (3,6,9,12,15)  if we multiply by 43 it is divisible by 3

Given:

43p is divisible by 3.

To find:

What is the largest value P can take.

Explanation:

In such type of problem we can find the value by trial and error technique.

Starting the value take p = 1

43p = 43 × 1

Check this value which is divisible or not divisible by 3

$\therefore$ $\frac{43}{3}$ not divisible by 3

take p = 2

43p = 43 × 2 = 86

$\therefore$ $\frac{86}{3}$ not divisible by 3

take p = 3

43p = 43 × 3 = 129

$\therefore$ $\frac{129}{3}$  divisible by 3

That is all multiple of three that is (3,6,9,12,15)  if we multiply by 43 it is divisible by 3

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