if 45 is subtracted from twice the greater of two numbers, it results in the other number. if 21 is subtracted from twice the smaller number, it results in the greater number. find the numbers
Answers
Answered by
356
let x be greater number and y be smaller number.
as per the question,
1st equation- 2x - 45 = y
2nd equation - x = 2y - 21
⇒ x+21/2 = y
substituting the value of y in equation 1, we get
2x - 45 = x+21/2
⇒ 2(2x-45) = x+21
⇒ 4x - x = 21+ 90
⇒ x = 111/3
∴ x = 37
so, greater no. is 37.
on putting value of x in equation one we get,
2x - 45 = y
2×37 - 45 = y
⇒ 74 - 45 = y
∴ y = 29
so, value of greater no. and smaller no. respectively are :- 37 and 29 respectively.
as per the question,
1st equation- 2x - 45 = y
2nd equation - x = 2y - 21
⇒ x+21/2 = y
substituting the value of y in equation 1, we get
2x - 45 = x+21/2
⇒ 2(2x-45) = x+21
⇒ 4x - x = 21+ 90
⇒ x = 111/3
∴ x = 37
so, greater no. is 37.
on putting value of x in equation one we get,
2x - 45 = y
2×37 - 45 = y
⇒ 74 - 45 = y
∴ y = 29
so, value of greater no. and smaller no. respectively are :- 37 and 29 respectively.
Answered by
128
First equation :- 2x-45 =y
Second equation :- 2y-21 =x
From i & ii
3y = 87
Y= 29 ☺️
Put y= 29 in (I) equation
X=37 ☺️
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