If 45 is subtracted from twice the greater of two numbers, it results in the other number. If 21 is
subtracted from twice the smaller number, it results in the greater number. Find the numbers class 10 cbse chapter 3
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Answer:
29 and 37
Step-by-step explanation:
Let "g" be the greater number, and "s" - the smaller number, then
2g - 45 = s
2s - 21 = g
2g - s = 45 ...... (1)
- g + 2s = 21 ...... (2)
Multiply equation (2) by 2, we get
- 2g + 4s = 42 ...... (3)
2g - s = 45 ........ (4)
Adding up (3) and (4), we get
3s = 87 ===> s = 29
g = 2×29 - 21 ===> g = 37
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