if 45 mL of 1.5 M AgNO3 is added to KCL how many grams of AgCl can be formed
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Explanation:
- AgNO3 + KCl ----> AgCl + KNO3
- From above balanced chemical reaction 1 mole of AgNO3 gives 1 mole of AgNO3.
Given :- Moles = Molarity × Volume (L)
= 1.5 × 0.045
= 0.0675 Moles
So, 0.0675 moles AgNO3 gives 0.0675 moles of AgCl
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