Question

If θ = 45, then find the value of 2sin2θ + 3 cosec2θ?​

Answer 1

$given \\ θ = 45$

$2 \sin(2 θ ) + 3 \cosec(2 θ) \\ \\ = 2 \sin(2 \times 45) + 3 \cosec(2 \times 45) \\ \\ = 2 \sin(90) + 3 \cosec(90) \\ \\ (we \: know \: \sin(90) = 1 \: and \: \cosec(90) = 1) \\ \\ = 2(1) + 3(1) \\ \\ = 2 + 3 \\ \\ = 5$