Math, asked by joshimishi33, 9 months ago

If 45000 = 2^a x 3^b x 5^c x 7^d
What is the value of a b c d

Answers

Answered by mhanifa
1

Answer:

a=3, b=2, c=4 and d=0

Step-by-step explanation:

Given:

  • 45000 = 2^a x 3^b x 5^c x 7^d

Prime factors of 45000:

  • 45000= 2^3 x 3^2 x 5^4

Compared to given it is clear that:

a=3, b=2, c=4 and d=0

(note 7^d=7^0=1, therefore d=0)

Hope it helps

Answered by jananigomez2
0

a=3 b=2 c=4 d=0

_______

5. | 45000

5. | 9000

2. | 1800

2. | 900

5. | 450

3. | 90

5. | 30

2. | 6

3. | 3

| 1

2³×3²×5⁴×7d=2a×3b×5c×7d

so a=3 b=2 c=4 d=0

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