If 45000 = 2^a x 3^b x 5^c x 7^d
What is the value of a b c d
Answers
Answered by
1
Answer:
a=3, b=2, c=4 and d=0
Step-by-step explanation:
Given:
- 45000 = 2^a x 3^b x 5^c x 7^d
Prime factors of 45000:
- 45000= 2^3 x 3^2 x 5^4
Compared to given it is clear that:
a=3, b=2, c=4 and d=0
(note 7^d=7^0=1, therefore d=0)
Hope it helps
Answered by
0
a=3 b=2 c=4 d=0
_______
5. | 45000
5. | 9000
2. | 1800
2. | 900
5. | 450
3. | 90
5. | 30
2. | 6
3. | 3
| 1
2³×3²×5⁴×7d=2a×3b×5c×7d
so a=3 b=2 c=4 d=0
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