if Ф=45degrees then what is value of 2sec²Ф + 3cosec²Ф
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Answered by
1
HI5!!
answer is 10
cos 45 is 1/root 2 ans so sec 45 is root 2 and sec^2 45 is 2
in the similar way,treat cosec and sin since sin=1/cosec
and so 2X2+3X2=10
answer is 10
cos 45 is 1/root 2 ans so sec 45 is root 2 and sec^2 45 is 2
in the similar way,treat cosec and sin since sin=1/cosec
and so 2X2+3X2=10
Answered by
0
sec^2 45=2
as root 2*root 2
so 2 sec^2= 4
cosec^2 is also 2
so 3 cosec^2= 6
so 4+6=10
as root 2*root 2
so 2 sec^2= 4
cosec^2 is also 2
so 3 cosec^2= 6
so 4+6=10
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