if 460 is divided by a natural number quetient is 6 more than five times the divisor &remainder is 1. find quotient &division
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By the Equation,
Divident=Divisor ×Quotient+remainder.
→460=Divisor×[(5divisor)+6]+1
Let divisor Be D
→460-1=D[5D+6]
→459=5D²+6D
→5D²+6D-459=0
So b²-4ac =36-(-9180)
=9216.
HereD=[-(6)±√9216]÷[2×5]
→D=[-6±96]÷10
So D =(-6+96)/10=90/10=9.
Or D=(-6-96)/10=(-102)/10=(-10.2)
So Divisor is 9 or -10.2
When Divisor is 9
Quotient=5(9)+6=45+6=51.
And When Divisor is -10.2
Quotient=5(-10.2)+6=-51+6=(-45).
Hope it Helps...
Regards,
Leukonov.
Divident=Divisor ×Quotient+remainder.
→460=Divisor×[(5divisor)+6]+1
Let divisor Be D
→460-1=D[5D+6]
→459=5D²+6D
→5D²+6D-459=0
So b²-4ac =36-(-9180)
=9216.
HereD=[-(6)±√9216]÷[2×5]
→D=[-6±96]÷10
So D =(-6+96)/10=90/10=9.
Or D=(-6-96)/10=(-102)/10=(-10.2)
So Divisor is 9 or -10.2
When Divisor is 9
Quotient=5(9)+6=45+6=51.
And When Divisor is -10.2
Quotient=5(-10.2)+6=-51+6=(-45).
Hope it Helps...
Regards,
Leukonov.
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