Question

if 47.256=4A+7B+2C+5D+6E,then find the value of 5A+4C+7C

Answer 1

This is not a standard mathematics question and can't be solved.

But if you take it as a trick question, you can find the values of A, B, C, D and E as follows:

47.256 = 4×10 + 7×1 + 2×0.1 + 5×0.01 + 6×0.001

Comparing it with 47.256=4A+7B+2C+5D+6E

we can take
A = 10
B = 1
C = 0.1
D = 0.01
E = 0.001

So 5A+4C+7C

= 5A + 11C

= 5×10 + 11×0.1

= 50 + 1.1

= 51.1


51.1 is your answer.

Answer 2

Answer:

If you notice the numbers before the variables are the same as in the answer. Therefore, all we need to know is about the placement in the number system.

So a has to be 10, b has to be 1, c has to be 0.1 d 0.01 and e 0.001.

You can now very easily find the value of 5a + 4c + 7e.

It will 50 + 0.4 + 0.007 = 50.407