Question

If 48 as a product of 2 consecutive even numbers, what are the two numbers?

Answer 1

let one of the number be x

the other number will be x+2

x × (x+2) = x^2 + 2x = 48

${x}^{2} + 2x = 48 \\ {x}^{2} + 2x - 48 = 0 \\ {x}^{2} + 8x - 6x - 48 = 0 \\ x(x + 8) - 6(x + 8) = 0 \\ (x + 8)(x - 6) = 0 \\ x + 8 = 0 \: \: \: \: \: x - 6 = 0 \\ x = - 8 \: \: x = 6$

hence first number is x = 6

second number is x+2 =8