If 4821X14Y is an eight digit number divisible by 72. How many rules can X and Y take
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Step-by-step explanation:
According to the divisibility rule, your question should be divisible by 9 and 8
divisibility rule of 9 is the sum of all digit should be divisible by 9
and divisibility rule of 8 is the last digit 3 should be divisible by 8
the sum of all digit is 4+8+2+1+X+1+4+Y = 20+X+Y
the last digit will be divisible by 8= 14Y/8
IF we put 3 in the place of y . the number will be exactly divisible by 8
And the value of x should be
20+X+Y
the value of y is 3 so the value of x would be 5
so that the sum of all digit divisible by 9
and the last 3 digits divisible by 8
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