Math, asked by nithika45, 11 months ago

if 49^2x-1=(343)^6 then find the value of 5^3x-13

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Answered by rajeev378
29
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Here is your answer
49 {}^{2x - 1}  = (343) {}^{6}  \\  {7}^{2(2x - 1)}  = ( {7}^{3} ) {}^{6}  \\  {7}^{4x - 2}  =  {7}^{3 \times 6}  \\ as \: same \: base \: so \: power \: is \: same \\ 4x - 2 = 3 \times 6 \\ 4x = 18 + 2 \\ 4x = 20 \\ x =  \frac{20}{4}  \\ x = 5
Now we have to find the value of
 {5}^{3x - 13}  \\  =  {5}^{3 \times 5 - 13}  \\  =  {5}^{15 - 13}  \\  =  {5}^{2}  \\  = 25
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Answered by ksabisheknarayanan20
3

Answer:

Hope it helps

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