Math, asked by shreeji90, 11 months ago

If 4921 × D = ABBBD then the sum of the digits of ABBBD×D is
A)19 B)20 C)25 D26​

Answers

Answered by anubhawkumar10p96dpt
13

@nswer is 19

4921×D= ABBBD.{ A six digit no.}

Let D be 7.

4921×7= 34447

Here,A=3

B=4 &

D=7

Sum of digit of 34447×7 will be = 241129 on adding digits .

2+4+1+1+2+9=19 i.e And...

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Answered by vaishvithaker
0

Answer:

Step-by-step explanation:

4921×D= ABBBD.{ A six digit no.}

Let D be 7.

4921×7= 34447

Here,A=3

B=4 &

D=7

Sum of digit of 34447×7 will be = 241129 on adding digits .

2+4+1+1+2+9=194921×D= ABBBD.{ A six digit no.}

Let D be 7.

4921×7= 34447

Here,A=3

B=4 &

D=7

Sum of digit of 34447×7 will be = 241129 on adding digits .

2+4+1+1+2+9=19

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