Math, asked by studentdps29, 10 months ago

if 49a^2-b=(7a+1/3)(7a-1/3) then value of be is

Answers

Answered by kamleshkantaria
2

Answer:

The answer is -

Step-by-step explanation:

To find the value of B

49a^{2} - b = (7a + 1/3)(7a - 1/3)

Follow the identity a^{2} - b^{2} = (a + b)(a - b)

(7a)^{2} - (?)^{2} = (7a + 1/3)(7a - 1/3)

? = 1/3

We have to find the value of B

b = (1/3)^{2}

  = 1/9[Value of b]

Answered by manjunpai2000
1

Answer is in the above given attachment

Attachments:
Similar questions