If 49a square -b = (7a+1/2)(7a-1/2),then the value of b is
Answers
Answered by
54
49a²-b = (7a+1/2)(7a-1/2)
RHS
(a+b)(a-b) = a²-b²
(7a+1/2)(7a-1/2) = (7a)²-(1/2)²
→ 49a²-(1/4)
by comparing LHS and RHS
49a²-b = 49a²-(1/4)
we can say b = 1/4.
I hope it helps you. Mark this answer as brainliest! :)
RHS
(a+b)(a-b) = a²-b²
(7a+1/2)(7a-1/2) = (7a)²-(1/2)²
→ 49a²-(1/4)
by comparing LHS and RHS
49a²-b = 49a²-(1/4)
we can say b = 1/4.
I hope it helps you. Mark this answer as brainliest! :)
Answered by
61
hi,
very nice nice question
given
49a² - b = ( 7a + 1/2 ) ( 7a - 1/2 )
first we need a formula which is ----
a² - b² = ( a + b ) ( a - b )
now
49a² - b =( 7a + 1/2 ) ( 7a - 1/2 )
=> 49a² - b = ( 7a )² - ( 1/2 )²
=> 49a² - b = 49a² - 1/4
=> - b = - 1/4
=> b = 1/4
.°. b = 1/4
====================================
very nice nice question
given
49a² - b = ( 7a + 1/2 ) ( 7a - 1/2 )
first we need a formula which is ----
a² - b² = ( a + b ) ( a - b )
now
49a² - b =( 7a + 1/2 ) ( 7a - 1/2 )
=> 49a² - b = ( 7a )² - ( 1/2 )²
=> 49a² - b = 49a² - 1/4
=> - b = - 1/4
=> b = 1/4
.°. b = 1/4
====================================
Priya12345678:
Thank you soo much
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