if 49a0b is divisible by 8and9 then what is the value of a
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a=1 or 6
Step-by-step explanation: 49a0b for divisible by 9 , 4+9+a+0+b=9k
k=2 or 3 for satisfing it
when k = 2 a+b=5 and b should be 0,2,46,8
a=1 b=4 , a=3 b=2, a=5 b=6 but only 104 is divisible by 8 so when a=1 b=4 49a0b will be divisible by 8 and 9
similarly when k=3
a=6 b=8 , a=8 b=9 here when a=6 then a0b will divisible by 8 so there are two value of a and b
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