Question

if (4a+3b)=10 ab=2 then find the value of (64a^3+27b^3)

Answer 1

Howdy !!

your answer is ---

Given, (4a+3b)=10 & ab = 2

we have ,
${64a}^{3} + {27b}^{3} \\ = {(4a)}^{3} + {(3b)}^{3} \\ = {(4a + 3b)}^{3} - 3 \times 4a \times 3b(4a + 3b) \\ = {10}^{3} - 36 \times 2 \times 10 \\ = 1000 - 720 \\ = 280$


hope it help you

Answer 2

Solution:-

given》(64a^3+27b^3), (4a+3b)=10 ab=2

(4a+3b)^3 = 》64a^3+27b^3 +36ab(4a+3b)

10^3 = 》64a^3+27b^3+72(10)

64a^3+27b^3 = 1000-720

(64a^3+27b^3 =280)ans