Question

If 4a + 3b = 10 and ab = 2, find the value of ( 64 a³+ 27 b³ )

Answer 1

Step-by-step explanation:

here we have to find the value of 64a^3 +27b^3 so we can see that 64 is the cube of 4 and 27 is cube of 3.

Given :-

=) (4a + 3b) =10 --------(1)

cubing both sides.

=) (4a+3b)^3 = (10)^3

=)64a^3 +27b^3 + 3×4a×3b(4a+3b) =1000

=)64a^3 +27b^3 +36ab(4a+3b) =1000---(2)

so also given that :---

=) ab = 2. and 4a +3b = 10

put these value in equation (2) we get.

=) 64a^3 +27b^3 +36×2×10 =1000

=) 64a^3 +27b^3 + 720 =1000

=) 64a^3 + 27b^3 = 1000 - 720

=) 64a^3 +27b^3 = 280

so the required value is 280 ans.

hope it helps you mate....