If (4a+3b)=10 and ab=2, find the value of (64a^3+27^3)
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Answer:
Hey Your Answer In This Attachment..
Step-by-step explanation:
Answer is 19779
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Answered by
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Answer:
4a+3b=10 ...(i)
b=2/a ...(ii)
put value of b in eq. (i)
4a +3×2/a = 10
4a +6/a =10
4a^2 + 6 = 10a
4a^2 - 10a + 6=0
4a^2 - 6a - 4a +6 = 0
2a(2a - 3) - 2(2a - 3) = 0
(2a-3)(2a-2) =0
....
2a-3 =0
a= 3/2 or
2a-2=0
a= 1
Using values of a,
when a=3/2,
64(3/2)^3 + 27^3 =
=64 × 27/8 + 27^3
= 8× 27 + 27^3
= 216 + 27^3
= 216 + 19683
= 19899
when a=1,
64(1)^3 + 27^3
= 64 + 19683
= 19747
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