Math, asked by vaishnavi1290, 11 months ago

If (4a+3b)=10 and ab=2, find the value of (64a^3+27^3)​

Answers

Answered by ankur2211
1

Answer:

Hey Your Answer In This Attachment..

Step-by-step explanation:

Answer is 19779

Attachments:
Answered by Anonymous
1

Answer:

4a+3b=10 ...(i)

b=2/a ...(ii)

put value of b in eq. (i)

4a +3×2/a = 10

4a +6/a =10

4a^2 + 6 = 10a

4a^2 - 10a + 6=0

4a^2 - 6a - 4a +6 = 0

2a(2a - 3) - 2(2a - 3) = 0

(2a-3)(2a-2) =0

....

2a-3 =0

a= 3/2 or

2a-2=0

a= 1

Using values of a,

when a=3/2,

64(3/2)^3 + 27^3 =

=64 × 27/8 + 27^3

= 8× 27 + 27^3

= 216 + 27^3

= 216 + 19683

= 19899

when a=1,

64(1)^3 + 27^3

= 64 + 19683

= 19747

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