Question

If 4a+5b+6c=0 then the set of lines ax+by+c=0 are concurrent at the point

Answer 1

Answer: Point is (2/3, 5/6)

Step-by-step explanation:

Given: The equation of line 4a+5b+6c=0

To Find: Point at which ax+by+c=0 is concurrent to given line.

Solution: In order to compare the given set of line multiply ax+by+c=0 with 6.

6(ax+by+c)=0

⇒6ax+6by+6c=0

Now, compare with set of line i.e. 4a+5b+6c=0

6x=4 ⇒ x=4/6 ⇒x=2/3

6y=5 ⇒ y=5/6

Thus, ax+by+c=0 is concurrent at point (2/3,5/6) to 4a+5b+6c=0.