Question

. If 4A2 = 60, 7A9 = 160 and 8A3 = 110, then find the value
of 3A2.

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Answer 1

Answer:

4A2=60

4+2=6*10=60

7A9=160

7+9=16*10=160

8A3=110

8+3=11*10=110

3A2=3+2=5*10=50

Answer 2

Answer:

no need of other values.....

we can just find 3A2 by using the formula 4A2=60

Explanation:

4A2 = 60

A2 = 60/4

A2 = 15

then

3A2=

3×VALUE OF A2

3×15

= 45

therefore 3A2 = 45

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