Question

If
4a² +b²
=40 and ab=6
find the value of 2a/b
​

Answer 1

ab = 6
a=6/b

Now,
4a² +b² =40
4(6/b)² +b² =40
144 + b^4 =40 b²
b^4 - 40 b² + 144 = 0
b^4 - 36 b² - 4 b² +144 =0
b² ( b² - 36) -4 ( b² - 36) = 0
(b² - 4) ( b² - 36) = 0

b²-4=0 or b² - 36 = 0

b² = 4 or. b² =36

b =2. or. b = 6


Therefore,
a=3. or. a=1



(a,b) = (3,2) or (1,6)



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Answer 2

Step-by-step explanation:

make b = 6/a

then substitute 4a2+ b2 = 40

you will get a4-10a2+9= 0