if 4and 1are the sum and product of a quadractic polynomial then the polynomial is
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10
Let α and β are zeros of required quadratic polynomial.
⇒ α+β=4 ---- ( 1 ) [ given ]
⇒ αβ=1 ----- ( 2 ) [ Given ]
The required polynomial,
x2−(α+β)x+(αβ)=0
Now, using ( 1 ) and ( 2 )
⇒ x2−4x+1=0
Answered by
3
Let alpha and beta are required quadratic polynomial
alpha + beta = 4 ----(1) [given]
alpha• beta = 1 ----(2) [given]
The required polynomial,
x²–(alpha+beta)x + (alpha•beta) = 0
Now, using 1 and 2,
━≫ x²–4x+1=0
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