If 4bc-a² = 0, then bx2 + ax + c = 0 has Options (a) Real and equal roots (b) Real and unequal roots (c) Non-real roots (d) Can't say
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Given: 4bc-a² = 0
bx²+ax+c = 0
To find: nature of roots
Step-by-step explanation:
(i) two distinct real roots, if a²-4bc > 0
(ii) two equal real roots, if a²-4bc = 0
(iii) no real roots, if a²-4bc < 0
Answer: Option (a) will be correct.
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