Question

If 4cos theta-3sin theta=3 find the value of 3cos theta+4 0​

Answer 1

Answer:

Using Trigonometric identities: Sin2x = 1- Cos2x

Sin2x = 1 – (4/5)2

= 1 - \frac{16}{25}1−2516

= \frac{(25 - 16)}{25}25(25−16)

= \frac{9}{25}259

Sin x = \frac{3}{5}53

:)