Question

if 4cos² x°-1=0,find i) x° ii)sin²x°+cos²x°​

Answer 1

Answer:

(i)x=45 ; (ii)sin²x+cos²x=1

Step-by-step explanation:

4cos²x - 1=0

4cos²x=1

cos²x=1/4

square rooting both side

cos x=1/√2

(i) cosx =cos 45

x=45

(ii)sin²45 + cos²45

(1/√2)² + (1/√2)²    [sin 45=1/√2]

=1/2 + 1/2

=1