if 4cosA=11sinA, find 11cosA-7sinA /11cosA+7sinA
Answers
Answered by
4
4/11 =tanA
4/137^1/2=sinA
11/137^1/2 =cosB
121/137^1/2 -28/121
4/137^1/2=sinA
11/137^1/2 =cosB
121/137^1/2 -28/121
prajwal4:
i not understand ur answer,pls ans me clearly
Answered by
23
Now
4cos A =11 sinS
=>cos A /sin A = 11/4
=>11 cos A/ 7 sin A =( 11 x 11)/(4 x 7)
=>11cos A/7 sin A= 121/28
=>(11cos A + 7 sin A)/(11 cos A - 7sin A)
=(121+28)/(121-28)
[componendo÷ndo]
= 149/93
therefore
11 cos A - 7 sin A/11 cos A + 7 sin A
=93/149
4cos A =11 sinS
=>cos A /sin A = 11/4
=>11 cos A/ 7 sin A =( 11 x 11)/(4 x 7)
=>11cos A/7 sin A= 121/28
=>(11cos A + 7 sin A)/(11 cos A - 7sin A)
=(121+28)/(121-28)
[componendo÷ndo]
= 149/93
therefore
11 cos A - 7 sin A/11 cos A + 7 sin A
=93/149
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