if 4cotA = 3 then sinA+cosA / sinA-cosA=
Answers
Answered by
1
Answer:
4cotA = 3 then sinA+cosA / sinA-cosA is 7
Step-by-step explanation:
4cotA=3
cotA=3/4
let a=3x , b=4x
By Pythagoras theorem
(3x)^2 + (4x)^2 = (y)^2
25x^2 = y^2
y = 5x
sinA+cosA / sinA-cosA
=4x/5x + 3x/5x / 4x/5x - 3x/5x
=7x/5x / x/5x
=7x/x
=7
Similar questions