Question

If 4fair coins are tossed simultanesly then find the probability that 2 heads and 2 tails appear​

Answer 1

Step-by-step explanation:

Let the random variable X be the number of heads that come up when a fair coin is tossed 4 times. Then X∼B(4,12). We want there to be exactly two heads (forcing the other two tosses to be tails), so P(X=2)=(42)(12)2(12)2=38.

Answer 2

Answer:

Let the random variable X be the number of heads that come up when a fair coin is tossed 4 times. Then X∼B(4,12). We want there to be exactly two heads (forcing the other two tosses to be tails), so P(X=2)=(42)(12)2(12)2=38.

Step-by-step explanation:

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