Question

if 4icap +3jcap+zkcap=13thenz=
​

Answer 1

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Here's ur answer

4i + 3j + zk = 13

|4i + 3j + zk| = 13

|4i + 3j + zk| = √(4²+3²+z²) = 13

4²+3²+z² = 13²

16+9+z² = 169

z²+25 = 169

z² = 169-25

z² = 144

z = ±12

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