Question

if 4kcal of heat is supplied to a gas and the volume of gas changes from 5L to 55L against a constant pressure of 2atm Find change in internal energy

Answer 1

Given,

q= 4 KCal

⟹ q =4000 cal

⟹q =4000 × 4.2 J

⟹ q= 16800J

Now

W= -2(50) L.atm

⟹W= -100 (101.3) J

⟹W= -10130 J

Change in Energy:

= 16800 +(- 10130) J

= 6670 J

Answer 2

Answer:

Given: Heat supplied Q=200 J

P

external

=1.5 atm, V

1

=0.5 L; V

2

=1.0 L

Using the relation, △U=Q+W

W=−P

ext

(V

2

−V

1

)=−1.5 atm(1.0−0.5) L; [1 L.atm=101.33 Joule]

W=−1.5×0.5 L.atm=−0.75 L.atm

W=−0.75×101.33 Joule

W=−75.99 Joule

⇒△U=200 J−75.99 J=124.0 J.

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