Question

if 4m+8, 2m²+3m+6, 3m²+4m+4 are three consecutive terms of an AP. find m​

Answer 1

Answer:2

Step-by-step explanation:

d= 2m*(squ)+3m+6-4m-8

d=2m*(squ)-m-2

And

d=3m*(squ)+4m+4-2m*(squ)-3m-6

d=m*(squ)+m-2

So,

2m*(squ)-m-2=m*(squ)+m-2

2m*(squ)-m*(squ)-m-m=0

m*(squ)=2m

m=2