if 4np3=5n+1p3 find the value of n?
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Please note the problem given is wrong because if we solve this we get n as negative which is not possible so if we change the question this way
If 5* nP3 = 4* (n+1)P3, find n?
then
nP3 = n*(n–1)*(n–2).
(n+1)P3 =(n+1)*n*(n–1).
Now,
5*n*(n–1)*(n–2) = 4* (n+1)*n*(n–1).
Or, 5(n−2) = 4(n+1).
Or, 5n−10 = 4n+4.
Or, 5n−4n = 4+10.
Hence, n = 14.
Note: nPr = [n! /(n -r)!].
Hope u understood
any confusion please fell free to contact me
If 5* nP3 = 4* (n+1)P3, find n?
then
nP3 = n*(n–1)*(n–2).
(n+1)P3 =(n+1)*n*(n–1).
Now,
5*n*(n–1)*(n–2) = 4* (n+1)*n*(n–1).
Or, 5(n−2) = 4(n+1).
Or, 5n−10 = 4n+4.
Or, 5n−4n = 4+10.
Hence, n = 14.
Note: nPr = [n! /(n -r)!].
Hope u understood
any confusion please fell free to contact me
soumenadhikari1994:
Sir, I have something to show you...
4np3 =5(n-1)p3.
4n(n-1)(n-2)=5(n-1)(n-2)(n-3)
4n=5(n-3)
n=15, is this correct or not?
yep u are right
Answered by
1
Answer:
n = 15
Step-by-step explanation:
Question : 4(nP3) = 5(n-1P3)
Formula Used
- nPr = [n!/(n-r)!]
Attachments:
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