Math, asked by simranmishra26, 6 months ago

If 4sinθ-3cosθ=0 ; then secθ.cosecθ =??

Answers

Answered by aravrajput511

0

Answer:

25/12

Step-by-step explanation:

4sinx=3cosx

Squaring both sides

16sin²x=9cos²x

16(1-cos²x)=9cos²x

16-16cos²x=9cos²x

16=25cos²x

cos²x=16/25

cosx=4/5

sinx=3/5

secxcosecx= 1/sinxcosx

=1/3/5*4/5

=25/12

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