Question

If 4sin A = 3, calculate cos A and tan A.​

Answer 1

Answer:

cos A = √7/4

tan A = 3/√7

Step-by-step explanation:

Given : 4sin A = 3

sin A = 3/4 = P/H

Perpendicular, P= 3

Hypotenuse, H=4

Base, B= ?

By Pythagoras Theorem,

H* = P* + B*

4*= 3* + B*

B* = 4*- 3*

B* = 16 - 9

B = √7

Now,

cos A = B/H = √7/4

tan A = P/B = 3/√7