Question

If 4sin theta= 3, then cos theta is equal to​

Answer 1

Answer:

$\frac{\sqrt{5} }{4}$

Step-by-step explanation:

4sinФ = 3

sinФ = $\frac{3}{4}$=$\frac{p}{h}$

$b^{2} = h^{2} -p^{2}$

b=$\sqrt{5}$

cos Ф = $\frac{b}{h}$ = $\frac{\sqrt{5} }{4}$

Answer 2

Answer:

The answer is $\frac{\sqrt 7}{4}$

Step-by-step explanation:

Given  $4\sin\theta=3 \Rightarrow \sin\theta=\frac{3}{4}$

Using  $\sin^2\theta+\cos^2\theta=1$

         $\Rightarrow \frac{9}{16}+\cos^2\theta=1\\\Rightarrow \cos^2\theta=1-\frac{9}{16}\\\Rightarrow \cos^2\theta=\frac{7}{16}\\\Rightarrow \cos\theta=\frac{\sqrt 7}{4}$