Question

if 4sin x -3cos x=0, then sec x•cosec x=?
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Answer 1

Answer:

0

Step-by-step explanation:

$4sin \: x \: - 3cos \: x \: = 0 \\ = > \frac{4}{cosec \: x} - \frac{3}{sec \: x} = 0 \\ = > \frac{ 4sec \: x - 3cosecx}{cose c \: x \: sec \: x} = 0 \\ = > 4sec \: x - 3cosec \: x = 0 \\ = > cosec \: x \: sec \: x \: ( \frac{4sec \: x}{\: cosec \: x} - \frac{3cosec \: x}{sec \: x} ) = 0 \\ = > cosec \: x \: sec \: x = 0$