Question

if 4sin² theta -3=0, and theta is acute, find sin theta and theta​

Answer 1

Answer:

$sinθ = \frac{ \sqrt{3} }{2} , \: θ=60°$

Step-by-step explanation:

$4 {sin}^{2} θ - 3 = 0 \\ 4 {sin}^{2} θ = 3 \\ {sin}^{2} θ = \frac{3}{4} \\ sinθ = \sqrt{ \frac{3}{4} } \\ sinθ = \frac{ \sqrt{3} }{2} \\ sinθ = sin60° \\ θ=60°$