If 4sinA + 3 sinA= 5 then what is the value of cosA?
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Step-by-step explanation:
3sinA+ 4cosA=5
squaring both sides,
9sin2A + 16cos2B + 24sinAcosA = 25 (1)
4sinA - 3cosA = x
squaring both sides,
16sin^2A + 9cos^2A – 24sinAcosA = x^ (2)
Add eqns. 1) and 2)
9 + 16 = x^2
x^2 = 25
x = +5 and x = -5
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